FuncDeclaration.leastAsSpecialized

Determine partial specialization order of 'this' vs g. This is very similar to TemplateDeclaration::leastAsSpecialized().

class FuncDeclaration
final
MATCH
leastAsSpecialized

Return Value

Type: MATCH

match 'this' is at least as specialized as g 0 g is more specialized than 'this'

Suggestion Box / Bug Report